If $a = 3, b = - 3$ , find the value of
$(a - 2)^{2} + (b - 2)^{2}$

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Solution

Let us substitute $a = 3$ and $b = - 3$ in the given expression $(a - 2)^{2} + (b - 2)^{2}$ as shown below:

$(a - 2)^{2} + (b - 2)^{2} = (3 - 2)^{2} + (- 3 - 2)^{2} = 1^{2} + (- 5)^{2} = 1 + 25 = 26$

Hence, $(a - 2)^{2} + (b - 2)^{2} = 26$ if $a = 3$ and $b = - 3$ .

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