If $a = 3, b = - 3$ , find the value of
$a^{2} + a b + b^{2}$

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Solution

Let us substitute $a = 3$ and $b = - 3$ in the given expression $a^{2} + a b + b^{2}$ as shown below:

$a^{2} + a b + b^{2} = 3^{2} + (3 \times - 3) + (- 3)^{2} = 9 - 9 + 9 = 18 - 9 = 9$

Hence, $a^{2} + a b + b^{2} = 9$ if $a = 3$ and $b = - 3$ .

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