If |a|=3, |b|=4 and |a+b|=1, then |a-b|=

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Solution

The correct option is C 7
$| a + b |^{2} + | a - b |^{2} = 2 | a |^{2} + 2 | b |^{2} \Rightarrow 1 + | a - b |^{2} = 2 (3)^{2} + 2 (4)^{2} \Rightarrow | a - b |^{2} = 49 \Rightarrow | a - b | = 7$

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