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Question

If a=3,b=4,c=5 each one of a,b and c is perpendicular to the sum of the remaining then a+b+c

A
52
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B
25
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C
52
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D
5
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Solution

The correct option is C 52
It is given that,
a(b+c)=0ab+ac=0 .........(1)
b(c+a)=0bc+ab=0 .......(2)
and c(a+b)=0ca+cb=0.......(3)
Add above three equations ab+bc+ca=0
Therefore
|a+b+c|=|a|2+|b|2+|c|2+2(ab+bc+ca)
=32+42+52+0=50=52

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