If a=3cos2A+sin4A, then which of the following is/are correct?
A
The minimum value of a is 1
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B
The minimum value of a is 0
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C
The maximum value of a is 3
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D
The maximum value of a is 4
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Solution
The correct option is C The maximum value of a is 3 Given : a=3cos2A+sin4A ⇒a=sin4A−3sin2A+3⇒a=(sin2A−32)2+34
We know that, 0≤sin2A≤1−32≤sin2A−32≤−1214≤(sin2A−32)2≤941≤(sin2A−32)2+34≤3