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Question

If A3×3 and detA=6, then det(2adj A) is equal to:

A
48
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B
8
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C
288
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D
12
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Solution

The correct option is C 288
Given |A3x3|=6
Now we know by property
|adjA|=|A|n1 & |aA|=an|A|
where A is matrix of nxn & a is scalar
So, |adjA|=A31
=62=36
& |2adjA|=23|adjA|
=8×36
=288

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