Question

If $A={30}^0$, then the value of

$\sin (A+{30}^0)+\cos (A+{60}^0)=\cos A$

if true then enter $1$ and if false then write $0$

Answer 1

Given, $A={30}^{\circ }$
To Prove, $\sin (A+{30}^0)+\cos (A+{60}^0)=\cos A$
L.H.S: $\sin (A+{30}^0)+\cos (A+{60}^0)$
= $\sin {60}^0+\cos {90}^0$
= $\sin {60}^0$
= $\frac{\sqrt{3}}{2}$
= $\cos {30}^0$
= $\cos A$