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Question

If A= 31-12, show that A2 − 5A + 7I = O use this to find A4.

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Solution

Given: A= 31-12Now,A2=AAA2=31-1231-12A2=9-13+2-3-2-1+4A2=85-53A2-5A+7IA2-5A+7I=85-53-531-12+71001A2-5A+7I=85-53-155-510+7007A2-5A+7I=8-15+75-5+0-5+5+03-10+7A2-5A+7I=0000=0Hence proved.Given: A2-5A+7I=0A2=5A-7I ...1A3=A5A-7I Multilpying by A on both sidesA3=5A2-7AIA3=55A-7I-7A From eq. 1A3=25A-35I-7AA3=18A-35I A4=18A-35IA Multilpying by A on both sidesA4=18A2-35AA4=185A-7I-35A From eq. 1 A4=90A-126I-35AA4=55A-126IA4=5531-12-1261001A4=16555-55110-12600126A4=165-12655-0-55-0110-126A4=3955-55-16

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