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Question

If A=350 , B=150 and C=400, then the value of tanAtanB+tanBtanC+tanCtanA is equal to

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is B 1
Given A=350 , B=150 and C=400,

tan(A+B+C)=tan(π2)=

We know that tan(A+B+C)=tanA+tanB+tanCtanAtanBtanC1tanAtanBtanBtanCtanCtanA

denominator =0

tanAtanB+tanBtanC+tanCtanA=1

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