If (a + 3b)(3a + b) = 4h2, then the angle between the lines represented by ax2+2hxy+by2=0 is
90∘
45∘
60∘
tan−112
= tan−1(√3a2+3b2+10ab−4aba+b)=60∘.
If the pair of straight lines given by Ax2+2Hxy+By2=0,(H2>AB) forms an equilateral triangle with line ax + by + c = 0, then (A + 3B)(3A + B) is