If a -3 ii-j-1-2 k- and b -2 i-3 j-k- find a -2 b - 2 a -b -

Given:a #8594;=3i^ j^ 2k^ #160;b #8594;=2i^+3j^+k^ #8756; #160;a #8594;+2b #8594;=3i^ j^ 2k^+2 #160;2i^+3j^+k^ #160; #160; #160; #160; ...

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Polynomials

If a →=3 ii-j...

Question

$If \vec{a} = 3 \hat{i} - \hat{j} - 2 \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} + \hat{k}, find (\vec{a} + 2 \vec{b}) \times (2 \vec{a} - \vec{b}) .$

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¯ ¯ ¯ a = 3 ¯ i - ¯ j - 2 ¯ ¯ ¯ k

¯ ¯ b = 2 ¯ i + 3 ¯ j + ¯ ¯ ¯ k

(¯ ¯ ¯ a + 2 ¯ ¯ b) \times (2 ¯ ¯ ¯ a - ¯ ¯ b) =

(3 A - 2 B) .

A = (2 i + 3 j - k)

B = (2 i - 5 j + 2 k) .

\vec{a} \cdot \vec{b}

\vec{a} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{b} = 4 \hat{i} - 4 \hat{j} + 7 \hat{k}

\vec{a} = \hat{j} + 2 \hat{k} and \vec{b} = 2 \hat{i} + \hat{k}

\vec{a} = \hat{j} - \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} - 2 \hat{k}

[\vec{a} \vec{b} \vec{c}]

\vec{a} = 2 \hat{i} - 3 \hat{j}, \vec{b} = \hat{i} + \hat{j} - \hat{k} and \vec{c} = 3 \hat{i} - \hat{k}

\vec{a} = \hat{i} - 2 \hat{j} + 3 \hat{k}, \vec{b} = 2 \hat{i} + \hat{j} - \hat{k} and \vec{c} = \hat{j} + \hat{k}

\vec{a} = 2 \hat{i} + 3 \hat{j} + \hat{k}, \vec{b} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{c} = - 3 \hat{i} + \hat{j} + 2 \hat{k}

\vec{a} and \vec{b}

\vec{a} = \hat{i} - \hat{j} and \vec{b} = \hat{j} + \hat{k}

\vec{a} = 3 \hat{i} - 2 \hat{j} - 6 \hat{k} and \vec{b} = 4 \hat{i} - \hat{j} + 8 \hat{k}

\vec{a} = 2 \hat{i} - \hat{j} + 2 \hat{k} and \vec{b} = 4 \hat{i} + 4 \hat{j} - 2 \hat{k}

\vec{a} = 2 \hat{i} - 3 \hat{j} + \hat{k} and \vec{b} = \hat{i} + \hat{j} - 2 \hat{k}

\vec{a} = \hat{i} + 2 \hat{j} - \hat{k}, \vec{b} = \hat{i} - \hat{j} + \hat{k}

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