If a -3 ii-jj-2 k- and b -2 ii-j-j-k- then find a - b - a -

Since #160;a #8594; #215;b #8594; #160;is #160;a #160;vector, #160;a #8594; #215;b #8594; #160;a #8594; #160;without #160;any #1 ...

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Orthogonal System of Vectors

If a →=3 ii-j...

Question

If $\vec{a} = 3 \hat{i} - \hat{j} + 2 \hat{k}$ and $\vec{b} = 2 \hat{i} + \hat{j} - \hat{k},$ then find $(\vec{a} \times \vec{b}) \vec{a} .$

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\vec{a} . (\vec{b} \times \vec{c})

\vec{a} = 2 \hat{i} + \hat{j} + 3 \hat{k}, \vec{b} = - \hat{i} + 2 \hat{j} + \hat{k}

\vec{c} = 3 \hat{i} + \hat{j} + 2 \hat{k}

If \vec{a} = 3 \hat{i} - \hat{j} - 2 \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} + \hat{k}, find (\vec{a} + 2 \vec{b}) \times (2 \vec{a} - \vec{b}) .

If \vec{a} = \hat{i} - \hat{j} and \vec{b} = \hat{j} + \hat{k}, then {|\vec{a} \times \vec{b}|}^{2} + {|\vec{a} . \vec{b}|}^{2} =________________.

\vec{a} = 2 \hat{i} - \hat{j} + \hat{k}

\vec{b} = \hat{i} + \hat{j} - 2 \hat{k}

\vec{c} = \hat{i} + 3 \hat{j} - \hat{k}

\vec{a}

λ \vec{b} + \vec{c}

\vec{a} \cdot \vec{b}

\vec{a} = \hat{i} - 2 \hat{j} + \hat{k} and \vec{b} = 4 \hat{i} - 4 \hat{j} + 7 \hat{k}

\vec{a} = \hat{j} + 2 \hat{k} and \vec{b} = 2 \hat{i} + \hat{k}

\vec{a} = \hat{j} - \hat{k} and \vec{b} = 2 \hat{i} + 3 \hat{j} - 2 \hat{k}

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