Question

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of $△ABC$ and AD is a median, then the coordinates of D are

(a) $(\frac{5}{2},3)$ (b) $(5,\frac{7}{2})$ (c) $(\frac{7}{2},\frac{9}{2})$ (d) none of these

Answer 1

Median AD of the triangle will divide the side BC in two equal parts.

Therefore, D is the mid-point of side BC.

D(x,y) = {(6+1)/2 , (5+4)/2} = {7/2 ,9/2}

(c) (7/2,9/2) is correct answer