If A(4, -3), B(3, -2) and C(2, 8) are the vertices of a triangle, then its centroid will be

(-3,3)

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(3,3)

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(3,1)

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(1,3)

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Solution

The correct option is C
(3,1)

Let the centroid of the triangle be (x, y).

The centroid of a triangle is given by $(\frac{x_{1} + x_{2} + x_{3}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$

$x = \frac{4 + 3 + 2}{3} = 3$

$y = \frac{- 3 - 2 + 8}{3} = 1$

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If A(4, -3), B(3, -2) and C(2, 8) are the vertices of a triangle, then its centroid will be

The correct option is C (3,1) Let the centroid of the triangle be (x, y). The centroid of a triangle is given by (x1+x2+x33,y1+y2+y33) x=4+3+23=3 y=−3−2+83=1

The correct option is C
(3,1)

Let the centroid of the triangle be (x, y).

The centroid of a triangle is given by $(\frac{x_{1} + x_{2} + x_{3}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$

$x = \frac{4 + 3 + 2}{3} = 3$

$y = \frac{- 3 - 2 + 8}{3} = 1$