Question

If $(a-5{)}^2+(b-6{)}^2=0$, then find the value of $(a+b-3)$?

• A. $8$
• B. $-8$
• C. $10$
• D. $-10$

Answer 1

The correct option is A $8$

Given,

$(a-5{)}^2+(b-6{)}^2=0$

This condition is only possible when $a-5=0,b-6=0$

$⟹a=5,b=6$

$\therefore$ value of $(a+b-3)=(5+6-3)=8$