If $(a - 5)^{2} + (b - 6)^{2} = 0$ , then find the value of $(a + b - 3)$ ?

8

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10

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- 10

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Solution

The correct option is A $8$
Given,
$(a - 5)^{2} + (b - 6)^{2} = 0$

This condition is only possible when $a - 5 = 0, b - 6 = 0$
$⟹ a = 5, b = 6$

$∴$ value of $(a + b - 3) = (5 + 6 - 3) = 8$

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