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If A = 5, 6, ...

Question

If A = {5, 6, 7, 8} and B = {7, 8, 9, 11}, then find A ∪ B.

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Solution

A ∪ B is the set that is defined as the elements present either in A (or) B (or) both.

A ∪ B = {5, 6, 7, 8, 9, 11}

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Q. In a shop, different sizes of shoes sold in a week are 7, 9, 8, 6, 7, 10, 6, 7, 8, 9, 11, 5, 6, 7, 8, 5, 9, 10, 9, 11, 12, 8, 3, 3, 5, 4, 6, 7, 4, 6, 7, 8, 8, 6, 9. What is the difference of the number between shoes sold of size 6 and size 7?

$For two sets A = {5, 6, 7, 8} & B = {7, 8, 9, 11} . A \cup B =$

Q. If U = {1, 2, 3, 4, 5, 6, 7, 8, 9} and A = {1, 2, 3, 4}, B = {2, 4, 6, 8}, C = {3, 4, 5, 6} then prove the following :
A' = {5, 6, 7, 8, 9}

A = {1, 2, 3, 4, 5},

B = {4, 5, 6, 7, 8}

C = {8, 9, 10, 11, 12},

n [A \times (B^{'} \cup C^{'})^{'}] =

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 5 & 7 0 & 7 & 9 11 & 8 & 9 \end{matrix} ⎤ ⎥ ⎦

, then trace of matrix A is.

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