Question

If a 5-digit number is formed by using the digits 1, 2,....9(without repetitions), then what is the probability that it will be an even number?

• A. $\frac{5}{13}$
• B. $\frac{4}{9}$
• C. $\frac{3}{8}$
• D. $\frac{5}{11}$

Answer 1

The correct option is B $\frac{4}{9}$

The number can be odd or even, depending on the last digit.
The last digit can be formed with any of $9$ numbers.
For the number to be an even number, last digit should be from the $4$ digits $2,4,6,8$.
So, probability that the number is even $=\frac{4}{9}$