Question

If A(7,5) , B(4,3) and C(-2,-3) are the vertices of a triangle, then find the slope angle, $\theta$ of side BC.

• A. ${60}^{\circ }$
• B. ${30}^{\circ }$
• C. ${45}^{\circ }$
• D. $0^{\circ }$

Answer 1

The correct option is C ${45}^{\circ }$

In side BC ,
$x_1=4,x_2=-2,y_1=3,y_2=-3$

Slope of Side BC = $\frac{y_2-y_1}{x_2-x_1}=\frac{-3-3}{-2-4}=1$
$\tan \theta =1$
$\therefore \theta ={45}^{\circ }$