If $A = {8, 16, 24, 32}$ and $B = {5, 25, 125}$ and $R$ is relation defined from A to B such that $a R b$ means $a < b$ for all $a \in A, b \in B$ and $(a, b) \in R,$ then $R =$ ___.

$R = {(8, 25), (8, 125), (8, 5), (16, 25), (24, 25), (32, 5), (32, 25)}$

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$R = {(8, 25), (8, 125), (16, 25), (16, 125), (24, 25), (24, 125), (32, 125)} .$

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$R = {(16, 25), (16, 125), (24, 5), (24, 25), (24, 125), (32, 25), (32, 125)}$

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$R = {(16, 5), (16, 125), (16, 25), (24, 25), (24, 5), (24, 125), (32, 25)}$

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Solution

The correct option is B
$R = {(8, 25), (8, 125), (16, 25), (16, 125), (24, 25), (24, 125), (32, 125)} .$

$R$ is relation defined from A to B such that $a R b$ means $a < b$ for all $a \in A, b \in B$ and $(a, b) \in R .$
Then, $R = {(8, 25), (8, 125), (16, 25), (16, 125), (24, 25), (24, 125), (32, 125)} .$

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If A={8,16,24,32} and B={5,25,125} and R is relation defined from A to B such that aRb means a<b for all a∈A,b∈B and (a,b)∈R, then R= ___.

The correct option is B R={(8,25),(8,125),(16,25),(16,125),(24,25),(24,125),(32,125)}. R is relation defined from A to B such that aRb means a<b for all a∈A,b∈B and (a,b)∈R. Then, R={(8,25),(8,125),(16,25),(16,125),(24,25),(24,125),(32,125)}.

If $A = {8, 16, 24, 32}$ and $B = {5, 25, 125}$ and $R$ is relation defined from A to B such that $a R b$ means $a < b$ for all $a \in A, b \in B$ and $(a, b) \in R,$ then $R =$ ___.