If $a = - 8, b = - 7$ and $c = 6$ verify that $(a + b) + c = a + (b + c)$

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Solution

$a = - 8, b = - 7, c = 6$
Taking LHS
$= (a + b) + c$
$= (- 8 - 7) + 6$
$= - 15 + 6$
$= - 9$
Taking RHS
$= a + (b + c)$
$= - 8 + (- 7 + 6)$
$= - 8 - 1$
$= - 9$
LHS=RHS
Hence proved

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