If A={A1,A2,A3,A4,A5,A6} be the set of six unit circles with centres at C1,C2,C3...C6 as shown in the diagram. The relation R on A is defined by (Ai,Aj)∈R⟺CiCj≤2√2,i,j∈{1,2...,6} where CiCj represents distance between the centres CiandCj , then
A
R is symmetric and transitive but not reflexive relation.
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B
R is transitive relation only.
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C
R is reflexive and symmetric but not transitive relation.
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D
R is neither reflexive nor transitive but it is symmetric relation
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Solution
The correct option is CR is reflexive and symmetric but not transitive relation. As distance between centres of same circle =0 ⇒CiCi=0≤2√2 ⇒(Ai,Ai)∈R∀i={1,2,3,4,5,6}
So, R is reflexive relation.
Let, (Ai,Aj)∈R ⇒CiCj≤2√2 ⇒CjCi≤2√2 ⇒(Aj,Ai)∈R
If (Ai,Aj)∈R⇒(Aj,Ai)∈R
So, R is symmetric relation.
From diagram (A1,A2)∈R and (A2,A3)∈R but (A1,A3)∉R
as, C1C3=4>2√2
So, R is not transitive relation.