If a, (a − 2), 3a are in AP, then a = ?
(a) −3
(b) −2
(c) 2
(d) 3

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Solution

(b) −2

If a, (a − 2) and 3a are in AP, then we have:
(a − 2) − a = 3a − (a − 2)
⇒ 2a = −4
∴ a = −2

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