If A a 2- 2 a - B 1 - a 2-2 - a and S 1-0- then prove that 1 - SA -1 - SB -1

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Identity (x-y)^2

If A a 2, 2 a...

Question

If A (a²,2a) ,B (1/a²,-2/a) and S( 1 ,0 ), then prove that 1/SA +1/SB =1

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A (a^{2}, 2 a) B (\frac{1}{a^{2}}, \frac{- 2}{a})

\frac{1}{S A} + \frac{1}{S B} = 1

S_{A} = 2 m + (2 m + 1) + (2 m + 2) + . . . + 4 m

S_{B} = (2 m + 1) + (2 m + 3) + (2 m + 5) + . . . + (4 m - 1),

A = (a t^{2}, 2 a t), B = (\frac{a}{t^{2}}, - \frac{2 a}{t}), S (a, 0)

\frac{1}{S A} + \frac{1}{S B} =

c_{1}, c_{2}, \dots, c_{n}

a = (a_{1}, a_{2}, \dots, a_{n})

(1, 2, \dots, n)

S (a) = n \sum i = 1 c_{i} a_{i} .

a \neq b

{1, 2, \dots, n}

If $| a | < 1 a n d | b | < 1$ , then the sum fo the series $1 + (1 + a) b + (1 + a + a^{2}) b^{2} + (1 + a + a^{2} + a^{3}) b^{3} + . . . i s$

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