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Byju's Answer

Standard VII

Mathematics

Representation of the Solution on a Number Line

If a! = aa-1a...

Question

If $a! = a (a - 1) (a - 2) (a - 3) . . .1$ , then find $X + Y + Z$ , given that $X Y Z$ is a three digit number such that $X Y Z = X! + Y! + Z!$ .

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Solution

The correct option is B $10$

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Similar questions

Q. Three digit numbers

x y z

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0, 1, 2, \dots 9

such that

x \leq y \leq z

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Find the total number of ways in which a 3- digit number xyz can be formed from the digits $1, 4, 5, 6, 7, 8 a n d 9$ such x,y,z that are in A.P and $x \neq y \neq z .$

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Q. Let

A = ⎡ ⎢ ⎣ \begin{matrix} x & y & z y & z & x z & x & y \end{matrix} ⎤ ⎥ ⎦

, where

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are real numbers such that

x + y + z > 0

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.
If

A^{2} = I_{3}

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If $x + y + z = 0$
then $x^{3} + y^{3} + z^{3}$ =___?

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If a!=a(a−1)(a−2)(a−3)...1, then find X+Y+Z, given that XYZ is a three digit number such that XYZ=X!+Y!+Z!.

The correct option is B 10

If $a! = a (a - 1) (a - 2) (a - 3) . . .1$ , then find $X + Y + Z$ , given that $X Y Z$ is a three digit number such that $X Y Z = X! + Y! + Z!$ .

The correct option is B $10$