The correct option is A (A × B) ∪ (A × C)
Let us write the set of (B ∪ C) first.
(B ∪ C) = {b,c,d}
A × (B ∪ C) = {(a,b),(a,c),(a,d),(b,b),(b,c),(b,d)}
Now Let us verify the given options :
(a) A ∪ B = {a,b,c}
(A ∪ B) × C = {(a,b),(a,c),(a,d),(b,b),(b,c),(b,d),(c,b),(c,c),(c,d)}
(b) A ∩ B = {b}
(A ∩ B) × C = {(b,b),(b,c),(b,d)}
(c) A ∪ B = {a,b,c}
(A ∪ B) ∪ C = {a,b,c,d}
(d) (A × B) = {(a,b),(a,c),(b,b),(b,c)}
(A × C) = {(a,b),(a,c),(a,d),(b,b),(b,c),(b,d)}
(A × B) ∪ (A × C) = {(a,b),(a,c),(a,d),(b,b),(b,c),(b,d)} which is equal to
A × (B ∪ C)