Question

If $A=\left\{\right(a,b,c):a,b,c\text{are prime numbers and}a+b+c=9\}$, then the number of ordered triplets is

Answer 1

Here, $a,b,c$ are prime numbers and $a+b+c=9$
$\Rightarrow a=2,b=2,c=5;$
$a=2,b=5,c=2;$
$a=5,b=2,c=2;$
$a=3,b=3,c=3$