If $A = {a, e, i, o, u, s, t}$ and $B = {p, r, s, o, t}$ , then $A △ B =$

{a, e, i, u, p, r}

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{a, i, u, p, r, t}

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{a, e, u, o, t}

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Solution

The correct option is A ${a, e, i, u, p, r}$
Given two sets: $A = {a, e, i, o, u, s, t}$ and $B = {p, r, s, o, t}$
Now, $A △ B = (A - B) \cup (B - A)$
Here $A - B = {a, e, i, u} & B - A = {p, r}$
$\Rightarrow A △ B = {a, e, i, u} \cup {p, r}$
$\Rightarrow A △ B {a, e, i, u, p, r}$

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If A={a,e,i,o,u,s,t} and B={p,r,s,o,t}, then A△B=

The correct option is A {a,e,i,u,p,r} Given two sets: A={a,e,i,o,u,s,t} and B={p,r,s,o,t} Now, A△B=(A−B)∪(B−A) Here A−B={a,e,i,u} & B−A={p,r} ⇒A△B={a,e,i,u}∪{p,r} ⇒A△B{a,e,i,u,p,r}

If $A = {a, e, i, o, u, s, t}$ and $B = {p, r, s, o, t}$ , then $A △ B =$

The correct option is A ${a, e, i, u, p, r}$
Given two sets: $A = {a, e, i, o, u, s, t}$ and $B = {p, r, s, o, t}$
Now, $A △ B = (A - B) \cup (B - A)$
Here $A - B = {a, e, i, u} & B - A = {p, r}$
$\Rightarrow A △ B = {a, e, i, u} \cup {p, r}$
$\Rightarrow A △ B {a, e, i, u, p, r}$