Question

If A = $(a_{ij}{)}_{2\times 2}$ , where $a_{ij}$ = i + j, then A is equal to

• A. $$\left[\begin{array}{cc}1& 1\\ 2& 2\end{array}\right]$$
• B. $$\left[\begin{array}{cc}1& 2\\ 1& 2\end{array}\right]$$
• C. $$\left[\begin{array}{cc}1& 2\\ 3& 4\end{array}\right]$$
• D. $$\left[\begin{array}{cc}2& 3\\ 3& 4\end{array}\right]$$

Answer 1

The correct option is D

$$\left[\begin{array}{cc}2& 3\\ 3& 4\end{array}\right]$$

$\begin{array}{c}A=\left[\begin{array}{cc}{a}_{11}& a_{12}\\ a_{21}& a_{22}\end{array}\right]=\left[\begin{array}{cc}1+1& 1+2\\ 2+1& 2+2\end{array}\right]=\left[\begin{array}{cc}2& 3\\ 3& 4\end{array}\right]\end{array}$