If A- - - - cos - sin - 0- -sin- cos- 0- 0 0 e- - then A- -1 in terms of function of - - is

|A(α, β)| = cos^2α e^β + sin^2α e^β = e^β Now, A (α, β)^ 1 = 1e^βadj (A(α, β)) = 1e^β[ e^βcosα amp; sinα e^β amp; 0; e^βsinα amp; ...

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Inverse of a Matrix

If Aα, β = [ ...

Question

If $A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦,$ then $A (α, β)^{- 1}$ in terms of function of $α, β$ is

A (α, - β)

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A (- α, - β)

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A (- α, β)

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none of the above

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A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

(A (α, β))^{- 1}

If A $(α, β) = ⎡ ⎢ ⎣ \begin{matrix} c o s α & s i n α & 0 - s i n α & c o s α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦, t h e n$

A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

A (α, β)^{- 1}

$A (α, β) = ⎛ ⎜ ⎝ \begin{matrix} c o s α & s i n α & 0 - s i n α & c o s α & 0 0 & 0 & e^{β} \end{matrix} ⎞ ⎟ ⎠ \Rightarrow {[A (α, β)]}^{- 1} =$

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