If A- - - - cos - sin - 0- -sin- cos- 0- 0 0 e- - then A- -1 in terms of function of - - is

|A(α, β)| = cos^2α e^β + sin^2α e^β = e^β Now, A (α, β)^ 1 = 1e^βadj (A(α, β)) = 1e^β[ e^βcosα amp; sinα e^β amp; 0; e^βsinα amp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Inverse of a Matrix

If Aα, β = [ ...

Question

If $A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦,$ then $A (α, β)^{- 1}$ in terms of function of $α, β$ is

A (α, - β)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A (- α, - β)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A (- α, β)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

(A (α, β))^{- 1}

If A $(α, β) = ⎡ ⎢ ⎣ \begin{matrix} c o s α & s i n α & 0 - s i n α & c o s α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦, t h e n$

A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

A (α, β) = ⎡ ⎢ ⎣ \begin{matrix} cos α & sin α & 0 - sin α & cos α & 0 0 & 0 & e^{β} \end{matrix} ⎤ ⎥ ⎦

A (α, β)^{- 1}

$A (α, β) = ⎛ ⎜ ⎝ \begin{matrix} c o s α & s i n α & 0 - s i n α & c o s α & 0 0 & 0 & e^{β} \end{matrix} ⎞ ⎟ ⎠ \Rightarrow {[A (α, β)]}^{- 1} =$

Join BYJU'S Learning Program