If $A$ and $B$ are acute angle such that $s i n A = c o s B$ then, find the value of $(A + B)$ .

45^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $90^{o}$
Given,
$s i n A = c o s B$
We know that, $c o s θ = s i n (90^{o} - θ)$
By applying the above formula, we get,
$\Rightarrow s i n A = s i n (90^{o} - B)$
Then,
$\Rightarrow A = 90^{o} - B \Rightarrow A + B = 90^{o}$

Suggest Corrections

Similar questions

Given that sin A= $\frac{1}{2}$ and cosB = $\frac{1}{\sqrt{2}}$ , then find the value of (A+B) (where A and B are acute angles).

°

If $sin (A + B) = 1, cos (A - B) = 1, 0^{\circ} \leq A + B \leq 90^{\circ}$ , Find $A$ and $B$ .

Given that $s i n A = \frac{1}{2}$ and $c o s B = \frac{1}{\sqrt{2}}$ , then find the value of $(A + B)$ .

Join BYJU'S Learning Program