If a&b are any two vectors, then (2a+3b)×(5a+7b)+a×b is equal to?
0
1
a×b
b×a
Explanation for the correct option:
Finding the value:
Given, a&b are two vectors
Now,
(2a+3b)×(5a+7b)+a×b=2ax(5a+7b)+3bx(5a+7b)+axb=10(axa)+14(axb)+15(bxa)+21(bxb)+axb=14axb–15(axb)+axb[(axa)&(bxb)=0and(bxa)=-(axb)]=0
Hence, correct option is (A)