If A and B are complementary angles, then

(a) sin A = sin B
(b) cos A = cos B
(c) tan A = tan B
(d) sec A = cosec B

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Solution

Given: and are are complementary angles

Since

Hence the correct option is

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Similar questions

A

B

sin A \times sec B =

If cos(A-B) = 3/5 and tanA*tanB = 2 then

(a) cosA*cosB= 1/5 (c) cos(A+B)= -1/5

(b) sinA*sinB= 2/5 (d) sinA*sinB=4/5

\frac{sin (A + B) + sin (A - B)}{cos (A + B) + cos (A - B)} = tan A

sin (A + B) + sin (A - B) = sin A

cos (A + B) + cos (A - B) = cos A

t a n A = 1, s i n A / c o s A =

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