If A and B are different matrices satisfying A3=B3andA2B=B2A, then
A
det(A2+B2)must be zero
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B
det (A-B) must be zero
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C
Both det(A2+B2) & det(A-B) must be zero
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D
At least one of det (A2+B2)or det (A-B) must be zero
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Solution
The correct option is DAt least one of det (A2+B2)or det (A-B) must be zero A3=B3⋯(i) and A2B=B2A⋯(ii)on subtracting
equation (i) and (ii) we get A3−A2B=B3−B2A⇒A2(A−B)=−B2(A−B) ⇒(A2+B2)(A−B)=O ⇒|(A2+B2).(A−B)|=0 ⇒det(A2+B2)=0 or det(A−B)=0