If A and B are foot of perpendicular drawn from point Q(a,b,c) to the planes yz and zc, then equation of plane through the points A,B and O is ............
A
xa+yb−zc=0
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B
xa−yb+zc=0
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C
xa−yb−zc=0
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D
xa+yb+zc=0
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Solution
The correct option is Axa+yb−zc=0 A and B are the foot of perpendiculars drawn from Q(a,b,c) to the planes yz and xz
∴A=(0,b,c) and B=(a,0,c)
Also, O=(0,0,0) is the origin
To determine the equation of plane, let's determine the normal vector