If a and b are integers and 95 - of a exceeds 95 - of b by c- then choose the most appropriate option-A- c is an integer but not a multiple of 19B- c is an integer and a multiple of 19C- c is a multiple of 19 but not an integerD- c may be a multiple of 19 and may be an integer

The correct option is D c may be a multiple of 19 and may be an integer 0.95 a = 0.95 b + c a b = 20/19 c The difference between two integers is an integer. ...

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Standard VI

Mathematics

Closure Property

If a and b ar...

Question

If a and b are integers and 95 $%$ of a exceeds 95 $%$ of b by c, then choose the most appropriate option.

c is an integer but not a multiple of 19

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c is an integer and a multiple of 19

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c is a multiple of 19 but not an integer

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c may be a multiple of 19 and may be an integer

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Solution

The correct option is D
c may be a multiple of 19 and may be an integer

0.95 a = 0.95 b + c

a - b = $\frac{20}{19} c$

The difference between two integers is an integer. So, $\frac{20}{19} c$ should be an integer.

'c' can be 1.9, so nothing can be said.

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If a and b are integers and 95% of a exceeds 95% of b by c, then choose the most appropriate option.

The correct option is D c may be a multiple of 19 and may be an integer 0.95 a = 0.95 b + c a - b = 2019 c The difference between two integers is an integer. So, 2019 c should be an integer. 'c' can be 1.9, so nothing can be said.

If a and b are integers and 95 $%$ of a exceeds 95 $%$ of b by c, then choose the most appropriate option.

The correct option is D
c may be a multiple of 19 and may be an integer

0.95 a = 0.95 b + c

a - b = $\frac{20}{19} c$

The difference between two integers is an integer. So, $\frac{20}{19} c$ should be an integer.

'c' can be 1.9, so nothing can be said.