If A and B are matrices of the same order, then (3A – 2B)^T is equal to ______________.

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Solution

(3A – 2B)^T

= (3A)^T− (2B)^T [For any two matrices X and Y, (X + Y)^T = X^T+ Y^T]

= 3A^T− 2B^T [(kX)^T = kX^T, where k is any constant]

If A and B are matrices of the same order, then (3A – 2B)^T is equal to $3 A^{T} - 2 B^{T}$ .

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