Question

If A and B are mutually exclusive events such that $P\left(A\right)=\frac{3}{5}$ and $P\left(B\right)=\frac{1}{5}$, then find $P(A\cup B)$.

• A. $\frac{2}{5}$
• B. $\frac{3}{5}$
• C. $\frac{4}{5}$
• D. None of these

Answer 1

Answer: (C)

$\frac{4}{5}$

$AandBaremutuallyexclusiveeventsthanP(A\cap B)=0P\left(A\right)=\frac{3}{5}andP\left(B\right)=\frac{1}{5}P(A\cup B)=P\left(A\right)+P\left(B\right)-P(A\cap B)=\frac{3}{5}+\frac{1}{5}-0=\frac{4}{5}$