wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a and b are numbers such that (a−4)(b+6)=0, then what is the smallest possible value of a2+b2?

A
16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
52
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 16
Since, (a4)(b+6)=0
So, the possible solutions are a=4
If b is any value and b =6
To get the smallest possible value of a2+b2, we have to choose either a or b needs to be 0.
i.e 02+(6)2=36
In this case, we have b=6 this may lead to the more value of a2+b2 if a =0.
While, if we choose b=0 this may lead to the smallest value of a2+b2=42+02=16
Hence, option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon