If $a$ and $b$ are positive integers such that $a + b = 9$ , then what is the value of $\frac{b - 9}{4 a}$ ?

- \frac{7}{2}

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- \frac{9}{4}

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- \frac{1}{4}

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\frac{1}{4}

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\frac{9}{4}

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Solution

The correct option is E $- \frac{1}{4}$
Given,
$a + b = 9$
Hence $, b = 9 - a$
To find: $\frac{b - 9}{4 a}$ $= \frac{(9 - a) - 9}{4 a}$
$= \frac{9 - a - 9}{4 a}$
$= \frac{- a}{4 a}$
$= - \frac{1}{4}$

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If a and b are positive integers such that a+b=9, then what is the value of b−94a?

The correct option is E −14Given,a+b=9Hence,b=9−aTo find: b−94a =(9−a)−94a=9−a−94a=−a4a=−14

If $a$ and $b$ are positive integers such that $a + b = 9$ , then what is the value of $\frac{b - 9}{4 a}$ ?

The correct option is E $- \frac{1}{4}$
Given,
$a + b = 9$
Hence $, b = 9 - a$
To find: $\frac{b - 9}{4 a}$ $= \frac{(9 - a) - 9}{4 a}$
$= \frac{9 - a - 9}{4 a}$
$= \frac{- a}{4 a}$
$= - \frac{1}{4}$