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Question

If a and b are rational and α,β be the roots of x2+2ax+b=0, then the equation with rational coefficients one of whose roots is α+β+α2+β2 is

A
x2+4ax2b=0
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B
x2+4ax+2b=0
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C
x24ax+2b=0
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D
x24ax2b=0
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Solution

The correct option is B x2+4ax+2b=0
Since α,β are roots of x2+2ax+b=0
α+β=2a and aβ=b.
Let y=α+β+α2+β2
(y+2a)2=α2+β2=(α+β)22αβ=4α22b
y2+4ay+2b=0
So, the required equation is x2+4ax+2b=0.

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