Question

If $a$ and $b$ are real numbers, the equation $3x-5+a-bx+1$ has a unique solution $x$ [The symbol $a$ $\ne$ $0$ means that a is different from zero]:

• A. For all $a$ and $b$
• B. if $a$ $\ne$ $2b$
• C. If $a$ $\ne$ $6$
• D. If $b$ $\ne$ $0$
• E. If $b$ $\ne$ $3$

Answer 1

The correct option is E If $b$ $\ne$ $3$