Question

If $a$ and $b$ are roots of the equation $x^2-px+q=0$, then the wire the value of $\frac{1}{a}+\frac{1}{b}$.

Answer 1

Consider the given equation.

$x^2-px+q=0$ ……. (1)

Since, $a$ and $b$ are roots of this equation.

So,

$a+b=p$

$ab=q$

Here,

$\frac{1}{a}+\frac{1}{b}$

$\Rightarrow \frac{a+b}{ab}$

$\Rightarrow \frac{p}{q}$

Hence, this is the answer.