If A and B are sets, then prove that A - B, A∩B and B- A are pair wise disjoint.
We need to show that (A - B) cap(A∩B)=ϕ, (A∩B)∩(B−A)=ϕ and (A−B)∩(B−A)=ϕ
The 3 sets A - B , A∩B and B−A may be represented by a venn diagram as follows.
It is clear from the diagram that the 3 sets are pairwise disjoint, but we shall giva a proof of it.
We first show that (A−B)∩(A∩B)=ϕ
Let x ϵ (A−B)
⇒x ϵA and x/ϵB
[by definition of A- B]
⇒x /ϵ A∩B. This is true for all x ϵ(A−B)
Hence (A−B)∩(A∩B)=ϕ
Finally , we show that (A−B)∩(B−A)=ϕ
Finally , we show that (A−B)∩(B−A)=ϕ
We have,
A - B = {x ϵ A:x /ϵB}
and B- A ={x ϵ B:x /ϵA}
Hence, (A−B)∩(B−A)=ϕ.