If A and B are square matrices of order 3 such that |A|=−1,|B|=3, then |3AB|=
A
−9
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B
−81
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C
−27
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D
81
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Solution
The correct option is B−81 Since, we know that |KA|=Kn|A| if A is of order n. Given, A and B both are of order 3. ∴AB is also of order 3. ⇒|3AB|=33|AB|=27|A||B| [∵|AB|=|A||B|] =27(−1)(3) =−81 Option B is correct.