If A and B are symmetric matrices of the same order and X=AB+BA and Y=AB−BA, then XYT is equal to
A
XY
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B
YX
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C
−XY
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D
None of these
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Solution
The correct option is C−XY Given, A and B are symmetric.
Then, AT=A and BT=B XYT=(AB+BA)(AB−BA)T =(AB+BA)((AB)T−(BA)T) =(AB+BA)(BTAT−ATBT) =(AB+BA)(BA−AB) =−(AB+BA)(AB−BA) =−XY ∴XYT=−XY