If α and β are the roots of the equation 2x2−3x+4=0, then the equation whose roots are α2 and β2 is
4x2+7x+16=0
4x2+7x+6=0
4x2+7x+1=0
4x2−7x+16=0
α + β = 32 and αβ = 2
α2+β2=(α+β)2−2αβ=94−4=−74
hence required equation x2−(α2+β2)x+α2β2=0
⇒ x2+74x+4=0 ⇒ 4x2+7x+16=0