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Question

If α and β are the roots of the equation 2x23x+4=0, then the equation whose roots are α2 and β2 is


A

4x2+7x+16=0

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B

4x2+7x+6=0

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C

4x2+7x+1=0

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D

4x27x+16=0

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Solution

The correct option is A

4x2+7x+16=0


α + β = 32 and αβ = 2

α2+β2=(α+β)22αβ=944=74

hence required equation x2(α2+β2)x+α2β2=0

x2+74x+4=04x2+7x+16=0


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