If a and b are the roots of the equation $x^{2} - 6 x + 6 = 0$ , then the value of $a^{2} + b^{2}$ are :

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Solution

The correct option is C 24
$(a + b) = 6$ and $a b = 6$
Therefore,
$a^{2} + b^{2} = (a + b)^{2} - 2 a b = 36 - 12 = 24$

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