If α and β are the roots of the equation x2+6x+λ=0 and 3α+2β=−20, then λ =
-16
α + β = -6 .....(i)
αβ = λ ......(ii)
and given 3α + 2β = -20 ......(iii)
Solving (i) and (iii), we get β = 2, α = -8
Substituting these values in (ii), we get λ = -16