If aandb are the roots of the equation x2+ax+b=0,a≠0,b≠0, the values of aandb are respectively
2and-2
2and-1
1and–2
1and2
– 1 and 2
The explanation for the correct option:
The given equation is x2+ax+b=0,a≠0,b≠0,
Since
Sumoftheroots=a+b=–aProductoftheroots=ab=b
Hence,
2a+b=0;ab–b=02a=–b;(a–1)b=02a=–b;a=1sinceb≠0b=–2a=1
Hence, the correct answer is option (C).
If ax+b=0 is a linear equation and a≠0 then value of x=...........
If a,b,c∈R and a≠0, c<0, and if the quadratic equation ax2+bx+c=0 has imaginary roots, then a+b+c is