If a and b are the roots of the equation x 2- px -1-0 and - c and d are the roots of the equation x 2- qx -1-0- then a - c b - c a - d b - d - -A- p 2- q 2B- a2-b2C- q2-p2D- q2-p2E- p 2

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Relation between Roots and Coefficients for Quadratic

If a and b ar...

Question

If a and b are the roots of the equation x²+px+1=0 and ; c and d are the roots of the equation x²+qx+1=0, then (a-c)(b-c)(a+d)(b+d)=?

p²-q²

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a²+b²

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q²-p²

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q²+p²

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p²

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Solution

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Similar questions

a, b

x^{2} + p x + 1 = 0

c, d

x^{2} + q x + 1 = 0

\frac{(a - c) (b - c) (a + d) (b + d)}{(q^{2} - p^{2})} =

a, b

x^{2} + p x + 1 = 0

c, d

x^{2} + q x + 1 = 0,

(a - c) (b - c) (a + d) (b + d) =

t a n A, t a n B

x^{2} - p x + q = 0

s i n^{2} (A + B)

a

b

x^{2} + px + 1 = 0 and c,

x^{2} + qx + 1 = 0

E = (a - c) (b - c) (a + d) (b + d)

Given that tan A, tan B are the roots of the equation $x^{2}$ - px + q = 0, then the value of $s i n^{2}$ (A + B) is

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